Acircular path 2feet wide has an inner diameter of 150 feet . how much farther is it around the outer edge of the path than around the inner edge?

12.56 feet

Step-by-step explanation:

Given: The width of the circular path= 2 feet

The inner diameter of circular path= 150 feet

Therefore, the inner radius of circular path=

Now, the outer radius= 75+2=77 feet

We know that the circumference=

Inner circumference=

Outer circumference=

The difference=

Hence, the outer edge of the path is 12.56 feet farther than the inner edge

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3