Mathematics, 11.10.2019 16:00 gamerdoesart

Can someone me on this promblem. also explain answer to me. p. s also marking the best most explained question

Can someone me on this promblem. also explain answer to me. p.s also marking the best most explai

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Answer from: madskate9993

Hello there! I can help you! We have the data shown, so let's put the data in order first. It should look like this:

8, 10, 12, 12, 12, 14, 14, 16, 20

The lower whisker represents 9 and the upper whisker represents 20. The data goes down no lower than 8. C is eliminated, because any part that goes down lower than 8 does not work. 4 is not part of the data set. To find the correctly plotted data, let's find the median. The media is the middle number. So cross the numbers out to find that. If you solve it correctly, our median is 12. This immediately eliminates A, because that graph shows a median of 14, not 12. That leaves B and D. Let's start finding out first quartile. For this part, we will not include the median when solving for it. We will solve for it by doing the first half. Cross out 8 and 12. That leaves us with 10 and 12. In this case, we add both of those numbers and divide by 2. 10 + 12 is 22. 22/2 is 11. Our first quartile is 11. Now, we will solve for the third quartile. Once again, cross out the numbers, 14 and 20 in this case. Now add 14 and 16 together. 14 + 16 is 30. 30/2 is 15. There. The third quartile is 15. Out of the remaining box plots left, B is the one that fits. Therefore, the answer is B.

Answer from: mmm119

Hello there! I can help you! We have the data shown, so let's put the data in order first. It should look like this:8, 10, 12, 12, 12, 14, 14, 16, 20The lower whisker represents 9 and the upper whisker represents 20. The data goes down no lower than 8. C is eliminated, because any part that goes down lower than 8 does not work. 4 is not part of the data set. To find the correctly plotted data, let's find the median. The media is the middle number. So cross the numbers out to find that. If you solve it correctly, our median is 12. This immediately eliminates A, because that graph shows a median of 14, not 12. That leaves B and D. Let's start finding out first quartile. For this part, we will not include the median when solving for it. We will solve for it by doing the first half. Cross out 8 and 12. That leaves us with 10 and 12. In this case, we add both of those numbers and divide by 2. 10 + 12 is 22. 22/2 is 11. Our first quartile is 11. Now, we will solve for the third quartile. Once again, cross out the numbers, 14 and 20 in this case. Now add 14 and 16 together. 14 + 16 is 30. 30/2 is 15. There. The third quartile is 15. Out of the remaining box plots left, B is the one that fits. Therefore, the answer is B.

Step-by-step explanation:

Answer from: Quest

⊂⊃⊂⊃ω $\frac{x}{y}\left[\begin{array}{ccc}1& 2& 3\\4& 5& 6\\7& 8& 9\end{array}\right] \left[\begin{array}{ccc}1& 2& 3\\4& 5& 6\\7& 8& 9\end{array}\right] \\ x^{2} \pi \pi \left[\begin{array}{ccc}1& 2& 3\\4& 5& 6\\7& 8& 9\end{array}\right] \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx x_{123} \left \{ {{y=2} \atop {x=2}} \right. \sqrt[n]{x} x_{123}$

step-by-step explanation:

i hope this : )

Answer from: Quest

you never say the total so we cant find the percentage used for petrol

step-by-step explanation:

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