Acell phone uses a 3.0 v battery. the circuit board it uses needs a 0.05 a current. what size resistor is needed to generate this current? ω

Ohm's law equation used to solve this problem is;
V = IR
where V - voltage
I - current passing 
R - resistance
voltage is the potential difference between 2 points and current passing through these 2 points is proportional to the potential difference, in other words voltage.
V∞I
Resistance is the constant in the equation 
the current required to pass through is 0.05 A (amperes)
the battery voltage is 3.0 V (volts)
substituting these values 
3 V = 0.05 A * R
R = 3/0.05 
R = 60 Ω (ohms)

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3