Prove that the square of an odd number is of the form 8k+1 g

Show that n is odd →∃m∈ℤ,n2=8m+1

Let k be an integer so that n=2k+1. Then n2=(2k+1)2=4k2+4k+1=2(2k2+2k)+1.

But this isn't equal to 8m+1, so can I change that into 4(2m)+1?

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

the answer will be b x² +x-1

step-by-step explanation: