Can someone me with this question? this is josh's solution for the equation: x^2-6x-7=0 x^2-6x-7=0 x^2-6x=7 x^2-6x+9=7+9 (x-3)^2=16 x-3=16 x=19 x-3=-16 x=-13 is josh's solution correct? explain.

No because x=3+√16=7 or x=3-√16=-1.

Josh's solution is incorrect.to solve this quadratic equation, one could factor or use the quadratic formula; i'll factor it.to factor, figure out which two numbers' product is -7 and whose sum is -6. the answer is -7 and 1: -7 * 1 = -7-7 + 1 = -6the factored polynomial is: (x - 7)(x + 1)to find the solutions of the equation, find its zeros. set each of the factors equal to 0 and solve for x.x - 7 = 0x = 7x + 1 = 0x = -1the solutions are 7 and -1, not -13 as josh says.

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.