Lin has 13 coins in her pocket that equal 40 cents. all the coins are dimes, d, and pennies, p. which combination of coins does lin have? use the table to answer the question.

The combination of coins are:

         3 dimes and 10 pennies.

Let there are d number of dines and p number of pennies.

Now as there are a total of 13 coins this means that:

                   d+p=13(1)

and also the total value of the coins is 40 cents.

1 dime=10 cents

Hence, d dime= 10 d cents

Also, 1 penny= 1 cent

Hence p penny= p cents

Hence, we get:

                     10d+p=40(2)

On subtracting equation (1) from (2) we get:

             9 d=27

on dividing both side by 9 we get:

                 d=3

On putting the value of d in equation (1) we get:

           3+p=13

i.e.  p=13-3

i.e.  p=10

The combination is:

    3 dimes and 10 pennies

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet