What values of a, b, c would you use in the quadratic formula for the following equation? 5x^2+9x=0 the expressions are too hard to do so pls tell me the answer

The answer is:

 a=5
 b=9
 c=0

 Explanation:

1. You can use the quadratic formula to solve quadratic equations with the following standard form:

 ax²+bx+c=0

 2. The quadratic formula is:

 x= (-b±√(b^2-4ac))/2a

 3. You have the following quadratic equation:

 5x²+9x=0

 4. Then:

 5x²+9x+0=0

 a=5
 b=9
 c=0

 5. When you substitute these values into the quadratic formula, you obtain:

 x1=-9/5
 x2=0

Sin(a)+cos(a)+cot(a)-1=2(csc(x)+1)