Find the magnitude and direction angle of v=8(cos135i+sin135j)

The magnitude of the vector will be given by:
 v = root ((8cos135) ^ 2 + (8sin135) ^ 2)
 v = root ((8) ^ 2 * ((cos135) ^ 2 + (sin135) ^ 2))
 v = root ((8) ^ 2 * (1))
 v = root ((8) ^ 2)
 v = 8
 The angle is:
 theta = Atan ((8sin135) / (8cos135))
 theta = Atan (tan135)
 theta = tan135
 
 The magnitude and direction angle are:
 v = 8
 theta = tan135

The correct answer is .44