1. a farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the field. he finds that the mean ph level of the samples is 5.7 with a standard deviation of 0.26. a. find the mean and standard deviation of the sampling distribution of all possible soil samples of size n = 32. round to three decimal places. b. construct a 95% confidence interval for the mean ph level of soil samples from every 1-foot by 1-foot section. show your work. even if you use technology, show the expression that is used to determine the margin of error for the interval. interpret the interval in a complete sentence. c. the farmer tested soil samples from 34 randomly selected sections from another field. he found the mean ph level of those samples to be 6.1 with a standard deviation of 0.34. construct a 95% confidence interval for the difference between the mean ph levels of all possible soil samples from both fields. show your work. even if you use technology, show the expression that is used to determine the margin of error for the interval. interpret the interval in a complete sentence.

A) The mean and standard deviation of the sampling distribution of all possible soil samples of size n = 32 are; Mean= 5.7 and standard deviation = 0.046

B) The 95% confidence interval for the mean pH level of soil samples from every 1-foot by 1-foot section is; CI = (3.694, 7.706)

C) The 95% confidence interval for the mean pH level of soil samples from every 1-foot by 1-foot section is; CI = (5.986, 6.214)

A) Sample size; n = 32

Mean; x' = 5.7

Original standard deviation; s = 0.26

Formula for standard deviation of the mean which is the standard error of the mean is;

s_m = (s/√n)

s_m = 0.26/√32

s_m = 0.046

B) Formula for confidence interval;

CI = x' ± z(s/√n)

where z is critical value at confidence level

We are given CL = 95%

From online sources, the Critical value at CL of 95% is z = 1.96

z(s/√n) is the margin of error

Thus;

ME = 1.96(0.26/√32)

ME = 2.006

CI = 5.7 ± 2.006

CI = (3.694, 7.706)

Interpretation is that we are 95% confident that the pH level of soil samples from every 1-foot by 1-foot section is between 3.694 and 7.706.

C) Sample size; n = 34

Mean; x' = 6.1

standard deviation; s = 0.34

Confidence interval is;

CI = x' ± z(s/√n)

where z is critical value at confidence level

We are given CL = 95%

From online sources, the Critical value at CL of 95% is z = 1.96

z(s/√n) is the margin of error

Thus;

ME = 1.96(0.34/√34)

ME = 0.114

Thus;

CI = 6.1 ± 0.114

CI = (5.986, 6.214)

The interpretation of the confidence interval is that;

We are 95% confident that the pH level of soil samples from every 1-foot by 1-foot section is between 3.694 and 7.706.

Read more about confidence intervals at; link

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}

5.7622

step-by-step explanation:

the ten thousandths place is the 2. you round it up if, that number in whatever place is 5 or higher.