Aschool bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel in the bus. how many ways can the students be seated if all of the second-grade students occupy the first row?

5P5×20P15

Step-by-step explanation:

A school bus has 25 seats, with 5 rows of 5 seats.

15 students from the first grade and 5 students from the second grade travel in the bus.

second-grade students occupy the first row.

The 5 students of second grade are to be seated in 5 seats,this can be done in:

5P5 ways where P is the permutation

Now 15 students from first grade are to be arranged in remaining 20 seats

This can be done in:

20P15 ways

Hence, total ways student can be seated is:

5P5×20P15

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p