Solve the linear system using substitution or elimintation. 3x-2y=-5, 4x+5y=47

{ 3 x - 2 y = - 5    * ( 4 )      ( I )
  4 x  +5 y = 47   * ( -3 )      (II)

 12 x - 8 y = - 20
-12 x - 15 y = -141

          - 23 y = -161  * ( - 1 )
           
             23 y = 161
                 
                  y = 161 / 23
                   
                  y =  7
   
For x 

3 x - 2 y = - 5    ( I )

3 x - 2 * 7 = - 5

3 x - 14 = - 5

3 x = - 5 + 14

3 x = 9

x = 9 / 3

x = 3

Solution:

x = 3 and y = 7

Hope this helps!.

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.