Compute the area of a triangle with sides. 10 x 10 x 16 area = ? square units

Ibelieve a better answer is the following: this is an isosceles triangle with congruent sides of 10 and a base of 16.    recall the area of a triangle is a =  the issue here is we know the base is 16, but we need to find the height.  to that, you would need to drop an altitude from the vertex of the triangle down to the base of 16.  this will be a perpendicular bisector and cut the base of the triangle into two halves of 8.. try drawing the picture.  now with the altitude sketched in, you'll see that it subdivides the original triangle into two congruent right triangles with the h(the height of the triangle as one leg and 8 as the other leg.  also notice the hypotenuse of the write triangle is 10.    substituting into the pythagorean theorem, we can solve for the height of the original isosceles triangle  a² + b² = c²  let's call 'a' the height herea² + 8² = 10²a² + 64 = 100a² = 36a = 6    now that we know the height is 6 and the base is 16, we can find the area of the original isosceles triangle.  a =    or the area would be 64 square units

Ithink the answer would be knew