Mathematics, 28.07.2019 11:30 alicc0529

4the ratio of corresponding dimensions of two similar solids is 3/4. the surface area of the first solid is 96 m². its volume is 720 m³. find the surface area and volume of the second solid. round each answer to the nearest tenth, if necessary. show your work 5 a globe in a brass stand has a diameter of 40 in. what is the volume of the globe to the nearest cubic inch? show your work.

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Answer from: shayle24

4.

The ratio is 3/4 for corresponding dimensions, the ratio of their surface areas is equal to the square of this ratio:

$\sf (\dfrac{3}{4})^2=\dfrac{S}{96}$

Simplify the exponent:

$\sf \dfrac{9}{16}=\dfrac{96}{S}$

Cross multiply:

$\sf 9S=1536$

Divide 9 to both sides:

$\sf S\approx 170.7~m^2$

So the surface area of the second solid is 54 square meters.

The ratio is 3/4 for corresponding dimensions, the ratio of their volumes is equal to the cube of this ratio:

$\sf (\dfrac{3}{4})^3=\dfrac{720}{V}$

Simplify the exponent:

$\sf \dfrac{27}{64}=\dfrac{720}{V}$

Cross multiply:

$\sf 27V=46080$

Divide 64 to both sides:

$\sf V\approx 1706.7~m^3$

5.

A globe is a sphere, use the formula for the volume of a sphere:

$\sf V=\dfrac{4}{3}\pi r^3$

The radius is half of the diameter, so the radius here is 40/2 = 20. Plug it in the formula, use 3.14 to approximate for Pi:

$\sf V=\dfrac{4}{3}(3.14)(20)^3$

Simplify the exponent:

$\sf V=\dfrac{4}{3}(3.14)(8000)$

Multiply:

$\sf V\approx \boxed{\sf 33,493~in^3}$

Answer from: erikacastro2421

Question 4:

---------------------------------------------------
Ratio of Dimension to Area
----------------------------------------------------
Dimension : Area
$\frac{3}{4} \ : \ (\frac{3}{4} )^2$
$\frac{3}{4} \ : \frac{9}{16}$

---------------------------------------------------
Find Area
----------------------------------------------------
Let x be the surface area of the second solid
$\frac{9}{16} = \frac{96}{x}$
$9x = 96 \times 16$
9x = 1536

$x = 1536 \div 9$
$x =170.7 m^2 (\ nearest \ tenth )$

---------------------------------------------------
170.7 m²
----------------------------------------------------

---------------------------------------------------
Ratio of Dimension to Volume
----------------------------------------------------
Dimension : Volume
$\frac{3}{4} \ : \ (\frac{3}{4} )^3$
$\frac{3}{4} \ : \ \frac{27}{64}$

---------------------------------------------------
Find Volume
----------------------------------------------------
Let x be the surface are of the second solid
$\frac{27}{64} = \frac{720}{x}$
$27x = 720 \times 64$
9x = 46080

$x = 146080 \div 27$
$x =1706.7 m^2 (nearest \ hundredth )$

---------------------------------------------------
1706.7 m³
----------------------------------------------------

Question 5
---------------------------------------------------
Find Radius
---------------------------------------------------
Radius = Diameter ÷ 2
Radius = 40 ÷ 2
Radius = 20

---------------------------------------------------
Find volume of the globe, which is a sphere
---------------------------------------------------
$Volume \ of \ sphere \ = \frac{4}{3} \pi x^{3}$

$Volume \ of \ sphere \ = \frac{4}{3} \pi (20)^{3}$

$Volume \ of \ sphere \ = 33510.3 in^3 \ ( \ nearest \ hundredth )$

---------------------------------------------------
33510.3 in³
----------------------------------------------------

Answer from: Quest

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

=3x+1

=3(2)+1

since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

=x+1

=2+1

now, let's find g(2)g(2):

g(x)

g(2)

=2x

=2⋅2

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

Answer from: Quest

ans789

step-by-step explanation:

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