What is the equation of a line that passes through(-6,2) and has a slope of -1/2 a. y=x/2-2 b. y= -x/2-1 c, y=2x+1 d. y=-2x-1

B.

Step-by-step explanation:

We are given that the equation of the line passes through the point (-6,2) and has a slope -1/2.

Substituting the given values in the formula for slope, we get,

i.e. =

i.e. -x-6 = 2y-4

i.e. 2y = -x-2

i.e.

Hence, the equation of the line is

mark branliest

step-by-step explanation:

.6 is 1/2 of 12

the answer is actually d. i just took the test

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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