Find the largest of three consecutive integers such that 3 times the sum of the first and the third integer is equal to 30 more than 4 times the second integer.

The largest would be 16 (the other two would be 14, 15).

Explanation:
Solve this by:
1- setting the first equal to x, the second to x+1 and the third to x+2.

2- write the equation given the description.
3(x+x+2) = 4(x+1) + 30.

3- solve.
3x + 3x + 6 = 4x + 4 + 30.
6x + 6 = 4x + 34.
2x = 28.
x =14

Do you need with the x value for the minimum? its always between the two intercepts for a parabola