Abox has a volume given by the trinomial x^3+4x^2-5x. what are possible dimensions of the box? use factoring. a. x, x-5 and x+1 b. x, x+5 and x-1 c. x, x+5 and x+1 d. x, x-5 and x-1

The correct answer is Choice B.

To factor this expression, we should first factor out the variable x.

We will have:
x(x^2 + 4x - 5)

Now, all we have to do is factor x^2 + 4x - 5.

The factors of this are (x + 5)(x - 1).

If you put all of the factors together, you have: x(x + 5)(x - 1) or Choice B.