What are the zeros of the quadratic function? f(x)=2x2+14x+24 enter your answers in the boxes.

Hi again!

The reason I've been showing my work is because I want to help you learn. This function is just the same as the other I solved earlier.

1) Set the function equal to 0

2x² + 14x + 24 = 0

2) Factorize the left side

2(x + 3)(x + 4) = 0

3) Set factors equal to 0

x + 3 = 0 or x + 4 = 0

x = 0 - 3 or x = 0 - 4

x = -3  or x = -4

Thus,

The zeros of this quadratic function are: x = -3 or x = -4

Free points baby. free points baby. free points baby. hell yeah!

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12