If 12^x^^2^+5x-4 =12^2x+6, what could be the value of x? x = 2 x = –5 x = 2, x = –5 no solution

x = 2, x = - 5

Explanation:

1) The given expression is not clear.

I will rewrite it using the math editor for better understanding



2) Since the bases are equal, the exponents are equal too.

=> x^2 + 5x - 4 = 2x + 6

Solve that quadratic equation step by step:

3) transpose 2x + 6 to the left side:

x^2 + 5x - 4 - 2x - 6 = 0

4) Combine like terms:

x^2 + 3x - 10 = 0

5) Factor:

(x + 5) (x - 2) = 0

6) Equal each factor to 0

x + 5 = 0 => x = - 5
x - 2 = 0 => x = 2

Those are the solutions x = - 5 and x = 2