The perimeter of a rectangle is 256 inches. how long are the sides if the length exceeds the width by 16 inches? mark lets x represent the width of the rectangle and writes the equation 2x + 2(x + 16) = 256. solving for x, the width of the rectangle is 56 60 68

X=56

Step-by-step explanation:

518,400

step-by-step explanation:

the area is multiplying all the given measurements together.

40 * 18 * 30 * 24 = 518,400

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)