Another geometry question : d
pentagon abcde and pentagon a'b'c'd'e' are shown on the coordinate plane below:
which two transformations are applied to pentagon abcde to create a'b'c'd'e'?
translated according to the rule (x, y) →(x + 8, y + 2) and reflected across the x-axis
translated according to the rule (x, y) →(x + 2, y + 8) and reflected across the y-axis
translated according to the rule (x, y) →(x + 8, y + 2) and reflected across the y-axis
translated according to the rule (x, y) →(x + 2, y + 8) and reflected across the x-axis

Translated according to the rule (x, y) →(x + 8, y + 2) and reflected across the x-axis

Step-by-step explanation:

The given polygons are translated and then reflected along x or y axis .

To determine the one from the given options the figure is translated and then reflected along x axis .Consider points A and A'.

A (-4,5) >A' (4,-7)

If 8 is added to x and 2 to y ordinates we have:

A(-4+8,5+2)= ( 4,7)

If this point is reflected along x axis we have the reflected point as (4,-7) which is point A'.

The same is true for all the other points of the polygon.

Hence, The two transformations are applied to pentagon ABCDE to create A'B'C'D'E is Translated according to the rule (x, y) →(x + 8, y + 2) and reflected across the x-axis.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!