Which equation results from applying the secant and tangent segment theorem to the figure? 12(a + 12) = 10^2 10 + 12 = a^2 10(a + 10) = 12^2 10(12) = a^2

The equation that results from applying the secant and tangent segment theorem to the figure is 12²  = 10(a+10)

According to the secant and tangent segment theorem, the square of the tangent line is equal to the product of the secant segments. Mathematically;

Tangent² = whole secant segment × External secant segment

DE² = AD × BD

Given

DE = 12

AD = a+10

BD = 10

Substitute into the formula:

12²  = 10(a+10)

Hence the equation that results from applying the secant and tangent segment theorem to the figure is 12²  = 10(a+10)

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