Arock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. how much time does it take for the rock to hit the ground?

Time taken by the rock to hit the ground is .

given,

initial velocity u = 16 ft/s

initial height h' = 5 feet

time of flight= ????....let us say 't'

gravitational acceleration=10 m/s²

angle of projection is not given, let us say it is 90degree

It is the motion of an object thrown up in the air at an angle from the horizontal (or ground), an object moving under gravitational acceleration pointed vertically downwards.

the object when projected will reach up to the maximum height, and then it will come back to the ground due to the effect of gravity.

as we know that empirical relation between height, initial velocity, and time of flight is

the time when a rock will just hit the ground the height will be zero.

we can say that

0=  16t-1/2*10*t²+5

5t²-16t-5=0

m/s

time taken by a rock to hit the ground is .

to get more about projectile motion refer to the link,

link

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.

asdsaddsa

step-by-step explanation: