What length is the shorter leg of a right triangle that has hypotenuse 50 in long and its perimeter is 112 inches?

The perimeter of a triangle is given by:

Perimeter = sum of three sides

We are given perimeter = 112 in.

Hypotenuse = 50 in.

Let us say the other two sides are a and b.

So , we have

...............(2)

In a right angle triangle we can apply pythagorean theorem,

a² + b² = c²

here c is hypotenuse which is 50 in.

a²+b² = 50²

a²+b² = 2500............(2)

Plugging the value of a from equation (1) in (2)

Factorising ,

So we have two values of b

b=14 and b=48

If b=14, a=48

If b=48, a=14

The shorter leg will  be 14 inches.

2? if not the correct answer you might need to provide more information

step-by-step explanation: