Don’t say a or just me plz and thx

A)P = 2l+2w
P =2l+2w≥40 should be
 2*6+2w≥40
12+2w≥40
2w≥40-12, 2w≥28
b) 2w≥28
w≥14
so smallest is 14

Information Given

Perimeter of a Parallelogram = 2l + 2w
Given that length = 6 feet and  Perimeter is no less that 40 feet


Construct the inequality

2(6) + 2w ≥ 40

12 + 2w ≥ 40


Take away 12 from both sides

2w ≥ 40 - 12

2w ≥ 28


Divide by 2 on both sides

w ≥ 14

The smallest possible value of the width is 14 feet


Answer (a) inequality: 12 + 2w ≥ 40 (b) Smallest value of w = 14.