Can you prove def is congruent to hgf? justify your answer

You are given that DE is congruent to GH (both have two hash marks). Since these are opposite angles EFD and HFG these angles are congruent (corresponding angles opposite congruent sides of a triangle are congruent). It is also true that these angle are vertical angles so you could prove they are congruent that way as well.

DF is congruent to FG (they both have 1 hash mark) so the angles opposite them are congruent (DEF and HGF). 

Now you have two angles in one triangle congruent to two angles in the pother. Since the angles in any triangle sum to 180, if two are congruent then the third must be as well so we know that angle D and angle G are congruent.

This is all we need to prove the triangles are congruent by SAS congruent to SAS. Specifically S (DE and GH), A (D and G) and S(DF and GF).

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote