Devon and michael ran a 5-mile race. devon ran 2 miles per hour faster than michael and finished the race 5 minutes before michael did. if x represents michael's speed (in miles per hour), which equation could represent this situation? answer choices 5x+2−5x=112 5x−5x+2=112 x+25−x5=112 x+25+x5=112 part 2 what was michael's speed? miles per hour

Let
x> Michael's speed  (in miles per hour)
y> Devon's speed  (in miles per hour)

we know that
y=x+2> equation 1
speed=distance/time> time=distance/speed
distance =5 miles
Michael's time=5/x
Devon's time=5/y
the difference [Michael's time-Devon's time]= 5 minutes

1 hour> 60 min
x> 5 min
x=5/60 hour

5/x-5/y=5/60> multiply by 60 both members
300/x-300/y=5> (300/x)-5=300/y> (300-5x)/x=300/y
y/300=x/(300-5x)> y=300x/(300-5x)> y=60x/(60-x)> equation 2

equation 1 =equation 2
x+2=60x/(60-x)> (60-x)*(x+2)=60x> 60x+120-x²-2x=60x
x²+2x-120=0
  
 using a graph tool >to resolve the second order equation
the solution is 
x=10
then
Michael's speed is 10 miles/hour
Devon's speed is 10+2> 12 miles/hour