Abox contains five slips of paper, each with one of the letters a, b, c, d, or e written on it. another box has four slips of paper, each with one of the numbers 1, 2, 3, or 4 written on it. without looking, nancy draws a slip of paper from each box. what is the probability that nancy draws the letter b from one box and the number 2 from the other box?

The probability that Nancy draws the letter B from one box and the number 2 from the other box is:

Step-by-step explanation:

We know that the probability of drawing a slip of paper from one box is independent of drawing a piece of slip from the other.

Let first box contain five slips of paper, each with one of the letters A, B, C, D, or E written on it.

This means that the probability of drawing B is:

ratio of the number of slips containing B to the total number of slips.

i.e.

Second box has four slips of paper, each with one of the numbers 1, 2, 3, or 4 written on it.

This means that the probability of drawing number 2 is:

ratio of the number of slips containing number 2 to the total number of slips.

i.e.

Hence,

Hence, the probability is:

60%

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

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