Horses cost $10, pigs cost $3, and rabbits are only $0.50. a farmer buys 100 animals for $100. how many of each animal did he buy? there are two correct answers.

You can use the following equation:

10h+3p+0.5r=100

This equation uses “h” “p” and “r” to represent the number of animals bought, each variable having a coefficient which is that animal's price. The right side is the total price.

You will now need a second equation so you can proceed to substitution/elimination:

h+p+r=100

This equation, using the same variables, represents the total number of animals to be bought.

We can eliminate the “h” variable by multiplying the bottom equation by -10, you now have the following:

10h+3p+0.5r=100

-10h-10p-10r=-1000

Add down and the result is:

-7p-9.5r=-900

You can set up a proportion

-9.5r=-900+7p

r=(-900+7p)/-9.5

And substitute in the original equation…

P.S. I challenge you to figure out the rest on your own because it is really just a tedious process of substitution and elimination from here and my phone is about to die. I'll check in later if you're still having problems.

It’s 24.6 after you round to the nearest tenths the answer should be 25.0