Tamara says that raising the number i to any integer power results in either -1 or 1 as the result, since i^2 = -1. do you agreed or disagree with tamera? explain

I agree only if you have even powers -- even negative ones.

1/i^2 = 1/-1 = - 1
i^0 also gives 1 So far no problem.

It is when you consider the odd numbers that you don't get 1 or -1 
You get either -i or i
i^(4n + 1) =  i
i^(4n - 1) = -i

I’m pretty sure the * means multiplication. so, if you multiply 5*1, it would equal 5. they are basically are-writing 5x1 as 5*1. so they would be… 5 10152025303540455055