Two cyclists, 132 mi apart, start riding toward each other at the same time. one cycles twice as fast as the other. if they meet 4 h later, at what average speed is each cyclist traveling?

If one cyclist is twice as fast as the the other cyclist
⇒ one cyclist would have covered 1/3 of the journey and the other 2/3

132 ÷ 3 = 44.
44 x 2 = 88.
The slower cyclist covered 44 miles whereas the faster cyclist covered 88 miles.

They met 4 hours later,
Speed of the slower cyclist = 44/4 = 11 miles/hour
Speed of the faster cyclist = 88/4 = 22 miles/hour


The average speed of the slower cyclist is 11 miles/hour and the average speed of the faster cyclist is 22 miles/hour.

Idon't know what's the answer lol