The ph measurements of water specimens from various locations along a given river basin are normally distributed with mean 8 and standard deviation 0.3. what is approximately, the probability that the ph measurements of a randomly selected water specimen is value between 7.5 and 8.2

The probability is 0.7011.
Z-scores are computed using the formula
z = (X - μ)/σ

The z-score associated with the lower level is

z = (7.5-8)/0.3 = -1.67

The z-score associated with the upper level is 

z = (8.2 - 8)/0.3 = 0.67

Using a z-table (http://www.z-table.com) we see that the area to the left of the lower limit, less than that, is 0.0475.  The area to the left of the upper limit, less than that, is 0.7486.  To find the area between them, we subtract:
0.7486 - 0.0475 = 0.7011.

If you make it a little more clear i can answer it

Ican’t sorry i would if i could