Arectangular sheet of metal has an area of 112 square inches. its perimeter is 44 inches. what are the dimensions of the sheet? ( hurry! this and other multiple questions due ! )

A) w * L = 112
B) 2w + 2L = 44
A) w = 112 / L then substituting this into B)
B) 2 * (112/L) + 2L = 44
B) 224 / L + 2L = 44
B) 224 + 2L^2 = 44L
B) 2L^2 -44L +224 = 0
L = 14
L = 8

Double Check
Width = 14  Length = 8
2*14= 28 2*8 = 16
28 + 16 = 44

14*8= 112
Correct!!!

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