What are the solutions to 6x^2-5x-4=0

To factor a quadratic equation that has a leading coefficient, multiply the most and least significant coefficients together. In this case 6 * -4 = -24

We need to find two numbers that multiply to -24 and add to -5. We will split the middle term into these two numbers.

6x^2 -8x + 3x - 4 = 0

Here you can see that we split -5x into -8x and 3x.

Now we can factor by grouping. To do this, group the first two terms together and the last two terms together. Factor out whatever you can.

(6x^2 - 8x) + (3x - 4)

2x(3x - 4) + 1(3x - 4)

Notice that the second group had nothing to factor out so we just pull out a 1. Now we can rearrange the factored form according to the distributive property.

(2x+1)(3x-4) = 0

So the solutions are x = -1/2 and x = 4/3

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