Can someone me with this question?

So the equation would be ...lets first look at the slope...

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1) so it is change in y over change in xor 1/1 =1//so that is the slope

2) now you need the "b' part of the equation...so that would be the y-intercept which is when x=0...so y=x+btake a random point on the line first...so 3,1..then plug it in1=1(3) +b.meaning b=-2

3)so then the equaiton would be y=x-2..
to check you can plug in a point on the line and see if it workslike 2,0 and it does

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step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

Ineed on quadratic equations to solve problems