Kay was walking along the bridge above the river. she accidentally lost her grip on her camera when she was trying to get it out to photograph massive bird nest in the trees. the height of the camera above the water can be modeled by the equation y= -16t^2+400, where t represents the seconds after the camera is dropped. how long will it take before kay sees the splash from the camera hitting the water?

It will take 5 seconds before Kay sees the splash from the camera hitting the water.

Step-by-step explanation:

Since the given equation representing height of the camera above the water and time t is

y = -16t²+400 where h = height above the water

and t = time in seconds after the camera is dropped.

Now we can say that the moment camera hits the water height becomes zero from which we can calculate the time taken.

-16t²+ 400 = 0

16t² = 400

t² = 400/16 = 25

t = √25 = 5 seconds.

Therefore time take by the camera before hitting the water is 5 seconds.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)