Janna has three flat plates, each the same size. she stores them in an l-shaped drawer, as shown so that they fit snuggly inside, with no spaces between the edges of the drawer and the plates. approximately how many square centimeters of the bottom of the drawer are not covered by plates?

 257.143 square centimeter (approx)

Step-by-step explanation:

Here, Three plates are stored in an L-shaped drawer, as shown so that they fit snuggly inside, with no spaces between the edges of the drawer and the plates.

Therefore,

Total area of L- shaped drawer which is not covered by these plates = Total covered area of the L-shaped drawer - Total area of three plates.

Since, the total area of L-shaped drawer= area of square of side 20 cm+ area of rectangle of length 40 and breadth 20.   ( by the given diagram)

Thus,  the total area of L-shaped drawer=

= 400+800

=1200 square cm

Here, the shape of plates are circular and having the radius of 10 cm. ( by the given diagram)

Therefore area of three circular plates =

= square cm

Total area of L- shaped drawer which is not covered by these plates = =257.142857143≈ 257.143 square cm.

step-by-step explanation:

why? because i noticed a pattern. 60 120. those numbers without the zero, make the 6 times tables leaving your answer to be b since 6 times 4 is 24 and adding a zero making it 240.

answer: the proof is mentioned below.

step-by-step explanation:

since, given:   lines bc = ef

prove:   lines ac > ef

          statements                                           reason

1. bc=ef                                           1. given

2. ac= ab+bc                                 2. because b is the point between the  

                                                            line segment ac

3.   ac > bc                                       3. because if a line segment is equal to

                                                          the sum of two line segments then it is

                                                          always greater then each of these

                                                          individual line segments

4. ac > ef                                         4. by equality property.