Using the digits {2, 3, . . , 8}, find the number of different 5-digit numbers such that: (a) digits can be used more than once. (b) digits cannot be repeated, but can come in any order. (c) digits cannot be repeated and must be written in increasing order. (d) which of the above counting questions is a combination and which is a permutation? explain why this makes sense.

As repetition is not allowed,

For first digit selection, we have 8 choices.

for second digit selection 7 choices.

Similarly, 6 choices for 3rd digit, 5 choices for 4th digit and 4 choices for 5th digit.

Hence, total choices 8 x 7 x 6 x 5 x 4 = 6720

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?