Acommunity organization was raising money by hosting a concert. the theater that they held the concert in could only seat 320 people. they decided to charge $8 for an adult and $5 for a child. if they hopes to raise $2000, what is the greatest number of children that could attend

186 children could attend.

The system of equations would be

A+C=320
8A+5C=2000

Solve the first equation for A by subtracting C from both sides:
A+C-C=320-C
A=320-C

Substitute this into the second equation:
8(320-C)+5C=2000
2560-8C+5C=2000
2560-3C=2000

Subtract 2560 from both sides:
2560-3C-2560=2000-2560
-3C=-560

Divide both sides by -3:
-3C/-3 = -560/-3
C = 186.7

Since we cannot have 0.7 of a child, there can be 186 children.

8-2x+3x2=6 and six is your answer