Suppose you are flying a kite that is 50 feet long. while flying, there is a constant gust of wind that blows the kite to an angle of 60° with the ground. how high, in feet, is the kite above the ground

Height of the kite above the ground =  43.301270189  feet

Step-by-step explanation:

The illustration above forms a right angled triangle. The right angle triangle have an hypotenuse, adjacent side and opposite sides.

The hypotenuse is given as 50 feet , the angle with the ground is 60°. Using the SOHCAHTOA principle we can find the height of the kite above the ground which is the opposite side .

sine 60°  = opposite/hypotenuse

sine 60° = opposite/50

0.8660254038 = opposite/50

cross multiply

opposite = 0.8660254038 × 50

opposite =  43.301270189  feet

Height of the kite above the ground =  43.301270189  feet

The image below is what the illustration forms(right angled triangle)

she drove 134 miles

step-by-step explanation:

the formula of a slope:

we have the points (-2, 7) and (2, 3). substitute: