100 points and brainliest! find the horizontal or oblique asymptote of f(x) = 2 x squared plus 5 x plus 6, all over x plus 1.

Hi there!

Find the vertical asymptotes by finding the values that make the equation undefined. Find the oblique asymptote by long polynomial division.

Vertical Asymptotes:

x = − 1

No Horizontal Asymptote

Oblique Asymptotes:

y = 2 x + 3

It should look something like the graph below:

Your friend, ASIAX

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47