What is the vertex of the graph of f(x) = |x – 13| + 11? (–11, 13) (–13, 11) (11, 13) (13, 11)

Absolute value functions result in a “kink”, or a vertex, in the graph when the values within the absolute value bars equal zero. In this case, you would need an x-value that zeroes out the term inside the absolute value bars.

This would make x=13 so that the value within the bars equals zero, and the y-value at x=13 would be y= 0+11=11.

Your vertex will be at the point (13, 11).