Use the drawing tool(s) to form the correct answer on the provided graph.

consider the function below.

h(x) = x^{2] - 2x - 8

plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of the function.

x-intercept (s):
 For this case h (x) = 0
 x2 - 2x - 8 = 0
 (x-4) * (x + 2) = 0
 x1 = 4
 x2 = -2
 y-intercept:
 For this case x = 0
 h (0) = (0)2 - 2 (0) - 8
 h (0) = - 8
 vertex:
 We derive the equation:
 h '(x) = x2 - 2x - 8
 h (x) = 2x - 2
 We match zero:
 2x-2 = 0
 x = 2/2
 x = 1
 We evaluate the function for x = 1
 h (1) = (1)2 - 2 (1) - 8
 h (1) = 1 - 2 - 8
 h (1) = -9
 The vertex is:
 (1, -9)
 axis of symmetry of the function:
 x = 1

Hello,
Please, see the attached files.
Thanks.

Suredude why not right