Many televisions are classified by the length of the diagonal of their screens. a 60 in. television has a screen height of 32 in. how wide is the television's screen?

The 60 inch is diagonal of or the hypotenuse of the TV so we are going to use a^2+b^2=c^2 and let width to be a, then we solve the problem.
a^2=c^2-b^2
oh, take the square root of both sides.
a=((c^2-b^2))^(1/2)
plug 60 for c, 32 for b, and the Width is equal to 50.75 for significant figures.

If is congruent to,then m is the midpoint