Two cars leave simultaneously from points a and b, the distance between which is 280 km. if the cars move to meet each other, they’ll meet in 2 hours. but if they move in the same direction, then the car going from point a will catch up with the car going from point b in 14 hours. what is the speed of each of the cars?

The car going from point A is moving at 80 km/h and the car going from point B is moving at 60 km/h.

Speed is the ratio of the distance travelled to time taken. It is given by:

Speed = distance / time

Let x represent the speed of car at point A and y represent the speed of car at point B.

If the cars move to meet each other, they’ll meet in 2 hours. Hence:

x = d₁ / 2

d₁ = 2x

Also:

y = d₂ / 2

d₂ = 2y

The distance between which is 280 km. Therefore:

d₁ + d₂ = 280

2x + 2y = 280   (1)

The car going from point A will catch up with the car going from point B in 14 hours if moving in same direction.  Hence:

x = d₁ / 14

d₁ = 14x

Also:

y = d₂ / 14

d₂ = 14y

d₁ = d₂ + 280

14x = 14y + 280  

14x - 14y = 280    (2)

Solving the equations simultaneously gives:

x = 80, y = 60

The car going from point A is moving at 80 km/h and the car going from point B is moving at 60 km/h.

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Speed of Car A is 80 km/h   and speed of Car B is 60 km/h.

Step-by-step explanation:

let v1 be speed of car A and v2 be speed of car B.

Then According to Question,

If they move in the same direction, then Car A will travel an ( x + 280 ) km while Car B will travel an x km. They both cover this in 14 hr.

using speed distance formula, we get

v1 × 14 = x + 280  

v2 × 14 = x  

v1 = v2 + 20 .................(1)

Moving towards each other, they'll collectively cover 280 km in 2 hours.

2 × (v1 + v2) = 280  

2 × (v2 + 20 + v2) = 280   (from eqn (1))  

v2 + v2 + 20 = 140  

2 × v2 = 120  

v2 = 60  

v1 = 60 + 20 = 80  

Therefore, Speed of Car A is 80 km/h   and speed of Car B is 60 km/h.

5/12, or 5: 12

step-by-step explanation:

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6