What angle θ3 does the ray refracted into the water make with the normal to the surface? use 1.33 for the index of refraction of water. g?

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θ₃ = 27.574°

Explanation:
To answer this question, we will use Snell's law twice.
Part 1: getting θ₂:
We have:
n1 is n of air = 1
n2 is n of glass = 1.58
θ₁ is the incident angle = 38°
θ₂ is the angle of refraction we want to find.
Apply Snell's law to get θ₂ as follows:
n1 sin(θ₁) = n2 sin(θ₂)
1 * sin(38) = 1.58 sin(θ₂)
sin (θ₂) = 0.3896
θ₂ = 22.933°

Part 2: getting θ₃:
We have:
n2 is n of glass = 1.58
n3 is n of water = 1.33
θ₂ is the incident angle = 22.933°
θ3 is the angle of refraction we want to find.
Apply Snell's law to get θ₂ as follows:
n2 sin(θ₂) = n3 sin(θ₃)
1.58 * sin(22.933) = 1.33 sin(θ₃)
sin (θ₃) = 0.462897
θ₂ = 27.574°

Hope this helps :)

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