Factor x2+12x+35 , i appreciate all the kind generous i can receive

X2+12x+35 should be written as  x^2+12x+35, where "^"
 denotes exponentiation.

Since the coefficient of the x^2 term is 1, we can focus on 35, finding its factors.  Note that 35 = 1*35, 5*7.  Also note that 5+7 = 12.

Thus, x^2+12x+35 can be re-written as (x+5)(x+7).  As a check, multiply 5 and 7; you get 35, which matches the original  x^2+12x+35.  Then add 5x to 7x, obtaining 12x, which also matches.