The capulet and montague families love writing. last year, each capulet wrote 4 essays, each montague wrote 6 essays, and both families wrote 100 essays in total. this year, each capulet wrote 8 essays, each montague wrote 12 essays, and both families wrote 200 essays in total. how many capulets and montagues are there?

Infinite solution

Step-by-step explanation:

Let, number of Capulet family = x and number of Montague family = y.

Since, last year, each Capulet wrote 4 essays and each Montague wrote 6 essays.

Moreover, total essays wrote last year are 100.

So, we get, 4x + 6y = 100.

Again, this year, each Capulet wrote 8 essays and each Montague wrote 12 essays.

Moreover, total essays wrote this year are 200.

So, we get, 8x + 12y = 200.

Thus, the system of equations is given by,

4x + 6y = 100.

8x + 12y = 200.

Dividing first equation by 2 and second equation by 4, we get the equation,

2x + 3y = 50.

Since, there is only one equation and two variables i.e. x and y.

There can be infinite number of possibilities for the values of x and y.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

b

step-by-step explanation: