Mathematics, 17.11.2019 10:31 sadiyahaaqilah

Which polynomial function could be represented by the graph below?
answer fast im timed
a. f(x) = x2 + x – 2
b. f(x) = 2x2 + 2x – 4
c. f(x) = x2 – x – 2
d. f(x) = 2x2 –2x – 4

Which polynomial function could be represented by the graph below? answer fast im timed

Answers: 3

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Answers

Answer from: Mystical3Sparkle

The parabola passes through the points (-2,0), (0,-4), and (1,0), then these points must satisfy the equation of the parabola.

For example:
1) (0,-4)→for x=0, y=-4→The independent term must be equal to -4
Only option b and d have independent term of -4

2) (1,0)→for x=1, y=0
Equation b. f(1)=2(1)^2+2(1)-4=2(1)+2-4=2+2-4→f(1)=0 Ok
Equation d. f(1)=2(1)^2-2(1)-4=2(1)-2-4=2-2-4→f(1)=-4 No

Option b. f(x)=2x^2+2x-4

Answer from: QueenZenobia

The polynomial function is $\boxed{f\left( x \right) = 2{x^2} + 2x - 2}$ that is represented by the graph.

Further explanation:

Given:

The options of the equations are as follows.

1. $f\left( x \right) = {x^2} + x - 2$

2. $f\left( x \right) = 2{x^2} + 2x - 4$

3. $f\left( x \right) = {x^2} - x - 2$

4. $f\left( x \right) = 2{x^2} - 2x - 4$

Explanation:

The graph passes through the points $\left( {0, - 4} \right)$ and $\left( { - 2,0} \right).$

Substitute 0 for x and -4 for $f\left( x \right)$ in equation $f\left( x \right) = {x^2} + x - 2$ to check the point satisfy the equation.

$\begin{aligned}- 4&={\left( 0 \right)^2}+ 0 - 2\\- 4&\ne- 2\\\end{aligned}$

The point doesn’t satisfy the equation.

Substitute 0 for x and -4 for $f\left( x \right)$ in equation $f\left( x \right) = 2{x^2} + 2x - 4$ to check the point satisfy the equation.

$\begin{aligned}- 4&= 2{\left( 0 \right)^2} + 2\left( 0 \right)- 4\\- 4&=- 4\\\end{aligned}$

The point satisfies the equation.

Substitute -2 for x and 0 for $f\left( x \right)$ in equation $f\left( x \right) = 2{x^2} + 2x -4$ to check the point satisfy the equation.

$\begin{aligned}0&=2{\left( { - 2}\right)^2} + 2\left( { - 2} \right) - 4\\0&= 8 - 4 - 4\\0&= 0\\\end{aligned}$

The point satisfies the equation.

Substitute 0 for x and -4 for $f\left( x \right)$ in equation to check $f\left( x \right) = {x^2} - x - 2$ the point satisfy the equation.

$\begin{aligned}- 4&= {\left( 0 \right)^2}- \left( 0 \right) - 2\\- 4&\ne- 2\\\end{aligned}$

The point doesn’t satisfy the equation.

Substitute 0 for x and -4 for $f\left( x \right)$ in equation $f\left( x \right) = 2{x^2} - 2x - 4$ to check the point satisfy the equation.

$\begin{aligned}- 4&= 2{\left(0 \right)^2} - 2\left( 0 \right) - 4\\- 4&=- 4\\\end{aligned}$

The point satisfies the equation.

Substitute -2 for x and 0 for $f\left( x \right)$ in equation $f\left( x \right) = 2{x^2} - 2x – 4$ to check the point satisfy the equation.

$\begin{galigned}0&= 2{\left( { - 2} \right)^2} - 2\left( { - 2} \right) - 4\\0&= 8 + 4 - 4\\0\ne8\\\end{aligned}$

The point doesn’t satisfy the equation.

Hence, the polynomial function is $\boxed{f\left( x \right) = 2{x^2} + 2x - 4}$ that is represented by the graph.Option (b) is correct.

Option (a) is not correct.

Option (b) is correct.

Option (c) is not correct.

Option (d) is not correct.

Learn more:

1. Learn more about inverse of the functionhttps://.

2. Learn more about equation of circle .

3. Learn more about range and domain of the function

Answer details:

Grade: High School

Subject: Mathematics

Chapter: polynomials

Keywords:quadratic equation, equation factorization, polynomial, quadratic formula, zeroes, function.

Answer from: Quest

Do something that you've always wanted to do. do something crazy, out of the ordinary but stay in your lanejaja hope it : d

Answer from: Quest

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.