Mathematics, 24.07.2019 03:00 bfgnnnbddf6830

Which expression is equivalent to the expression shown below? -1/2(-3/2x + 6x + 1) -3x a)3/2x - 1/2 b)6 3/4x - 1/2 c)-3/4x + 1/2 d)-5 1/4x - 1/2

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The correct answer is: [D]: " (-5 $\frac{1}{4}$ )x − $\frac{1}{2}$ " .
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Explanation:
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" -1/2(-3/2x + 6x + 1) − 3x " ;

= (-1/2 * -3/2 x) + (-1/2 * 6x) + (-1/2 * 1) − 3x ;

= [ (-1 *-3) /(2*2)] x + (-3x) + (-1/2) ] − 3x ;

= [ (3/4)x − 3x − (1/2) ] − 3x ;

=   (3/4)x − 3x − (1/2) − 3x ;

= ?? ;   → Combine the "like terms" ;

→ "(3/4)x − 3x − 3x " = ?? ;

→ "(3/4)x − 3x = "(-9/4)x";

→ "(-9/4)x − 3x = "(-21/4)x " = " (-5 $\frac{1}{4}$ )x " ;

→ The answer is: " (-5 $\frac{1}{4}$ )x − $\frac{1}{2}$ " ;
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→ which is:
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→   Answer choice: [D]: " (-5 $\frac{1}{4}$ )x − $\frac{1}{2}$ " .
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Answer from: Quest

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

The graph below shows the value of a $100 deposited into three different accounts over a period of 2

Answer from: Quest

step-by-step explanation:

idk

i know the way

and

idk

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Which expression is equivalent to the expression shown below? -1/2(-3/2x + 6x + 1) -3x a)3/2x - 1/2...

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