If the volume of a cylinder is 471 cubic centimeters what are the volume the radius and height of a cone that fits inside the cylinder and shares the same base and height measurements

Let
r> the radius of the cylinder
h> the height of the cylinder

we know that

[volume of a cylinder]=pi*r²*h > 471 cm³=pi*r²*h

[volume of a cone]=pi*r²*h/3
the radius of he cylinder is equals to the radius of a cone
the height of the cylinder is equals to the height of a cone
therefore
[volume of a cone]=[volume of a cylinder]/3> 471/3> 157 cm³

the answer is
the volume of a cone is 157 cm³
 

Ithink if im not mistaking b is -3 but im not a 100% sude